Cron run problem
Posted: Wed Mar 16, 2016 8:34 am
Hello,
I am having the below problem:
/usr/local/vesta/bin/v-update-sys-queue disk
sed: -e expression #1, char 3: unknown command: `
'
sed: -e expression #1, char 3: unknown command: `
'
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
All other crons seems to be working fine. I haven't changed anything on that server for several days. Any ideas?
Thanks.
I am having the below problem:
/usr/local/vesta/bin/v-update-sys-queue disk
sed: -e expression #1, char 3: unknown command: `
'
sed: -e expression #1, char 3: unknown command: `
'
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
All other crons seems to be working fine. I haven't changed anything on that server for several days. Any ideas?
Thanks.