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Cron run problem
Cron run problem
Hello,
I am having the below problem:
/usr/local/vesta/bin/v-update-sys-queue disk
sed: -e expression #1, char 3: unknown command: `
'
sed: -e expression #1, char 3: unknown command: `
'
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
All other crons seems to be working fine. I haven't changed anything on that server for several days. Any ideas?
Thanks.
I am having the below problem:
/usr/local/vesta/bin/v-update-sys-queue disk
sed: -e expression #1, char 3: unknown command: `
'
sed: -e expression #1, char 3: unknown command: `
'
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
All other crons seems to be working fine. I haven't changed anything on that server for several days. Any ideas?
Thanks.
Re: Cron run problem
Hi,
What OS on your server ?
What OS on your server ?
Re: Cron run problem
Ubuntu 14.04.4 x64
Re: Cron run problem
Any ideas?
Re: Cron run problem
Imperio?
Re: Cron run problem
sed: -e expression #1, char 3: unknown command: `
'
sed: -e expression #1, char 3: unknown command: `
'
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
'
sed: -e expression #1, char 3: unknown command: `
'
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
/usr/local/vesta//func/main.sh: line 485: 1
1: syntax error in expression (error token is "1")
Re: Cron run problem
Nobody can help?
Re: Cron run problem
Hi, alexcy
Sorry for the later reply
I will check this problem on our test servers with Ubuntu
Sorry for the later reply
I will check this problem on our test servers with Ubuntu
Re: Cron run problem
I cant reproduce this problem on our test servers
Grant access to your server. I'll check the problem on your server
Grant access to your server. I'll check the problem on your server
Re: Cron run problem
It may be variables:
or viewtopic.php?uid=17&f=16&t=5075&start=0#p15173
Code: Select all
export VESTA=/usr/local/vesta/